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vb.net ean 13 reader

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vb.net ean 13 reader

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byte b = (byte) 0xf1; Systemoutprintln("b = 0x" + hex[(b >> 4) & 0x0f] + hex[b & 0x0f]); } }

Figure 5-5

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vb.net ean 13 reader

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As you have just seen, the >> operator automatically fills the high-order bit with its previous contents each time a shift occurs This preserves the sign of the value However, sometimes this is undesirable For example, if you are shifting something that does not represent a numeric value, you may not want sign extension to take place This situation is common when you are working with pixel-based values and graphics In these cases, you will generally want to shift a zero into the high-order bit no matter what its initial value was This is known as an unsigned shift To accomplish this, you will use Java s unsigned, shift-right operator, >>>, which always shifts zeros into the high-order bit The following code fragment demonstrates the >>> Here, a is set to 1, which sets all 32 bits to 1 in binary This value is then shifted right 24 bits, filling the top 24 bits with zeros, ignoring normal sign extension This sets a to 255

vb.net ean 13 reader

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int a = -1; a = a >>> 24;

2 Obtain a reference to the instance of the Display class 3 Create an instance of the Command class to return from the help page 4 Create an instance of the Command class to exit the MIDlet 5 Create an instance of the Form class 6 Create an instance of the TextBox class that contains the help text 7 Associate the instance of the Back Command class with the instance of the TextBox class 8 Associate the instance of the Exit Command class and the instance of the Help Command class with the instance of the Form class 9 Associate a CommandListener with the instance of the Form class 10 Associate a CommandListener with the instance of the TextBox class 11 Display the form 12 Evaluate the command that the user entered into the small computing device 13 If the command is the Back command, display the form 14 If the command is the Exit command, terminate the MIDlet 15 If the command is the Help command, display the text box

Here is the same operation in binary form to further illustrate what is happening: 11111111 11111111 11111111 11111111 >>>24 00000000 00000000 00000000 11111111 1 in binary as an int 255 in binary as an int

20 1

The >>> operator is often not as useful as you might like, since it is only meaningful for 32- and 64-bit values Remember, smaller values are automatically promoted to int in expressions This means that sign-extension occurs and that the shift will take place on a 32-bit rather than on an 8- or 16-bit value That is, one might expect an unsigned right shift on a byte value to zero-fill beginning at bit 7 But this is not the case, since it is a 32-bit value that is actually being shifted The following program demonstrates this effect:

vb.net ean 13 reader

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vb.net ean 13 reader

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vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader

vb.net ean 13 reader